Question

Rozwiaż równanie
(x-1)²(x₂-4)=0
(x²-3x)=0
x³-6x+8=0
x³+2x²-4x-8=0

Answer 1

(x-1)²(x₂-4)=0
(x-1)(x-1) (x²-2²) = 0
(x-1)(x-1)(x-2) (x+2)=0
X-1 = 0 ∨ x-2 = 0 ∨ x+2=0
x=1 ∨ x=2 ∨ x=-2


(x²-3x)=0
delta = b²-4ac
delta = (-3)² - 4 * 1 * 0
delta = 9 - 0
delta = 9
√delty = 3
x₁ = (-b-√delty)/2a
x₁ = (3-3)/2
x₁ =0/2
x₁ =0
x₂ = (-b+√delty)/2a
x₂= (3+3)/2
x₂=6/2
x₂=3
x₁= 0, x₂= 3


x³+2x²-4x-8=0
x²(x+2)-4 (x+2) = 0
(x²-4)(x+2)=0
(x²-2²)(x+2)=0
(x-2)(x+2)(x+2)=0
x-2=0∨x+2=0
x=2∨x= -2