(4x+1)/(4x-8)-(x+1)/(x+2)=(4x+1)/4(x-2)-(x+1)/(x+2)=(4x+1)(x+2)/4(x-2)(x+2)-4(x+1)(x-2)/4(x-2)(x+2)=[4x²+8x+x+2-4(x²-2x+x-2)]/4(x+2)(x-2)=(4x²+9x+2-4x²+4x+8)/4(x+2)(x-2)=(13x+10)/4(x+2)(x-2) , dla x-2≠0 ∧ x+2≠0 czyli x≠2 ∧ x≠-2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
(4x+1)/(4x-8)-(x+1)/(x+2)=(4x+1)/4(x-2)-(x+1)/(x+2)=(4x+1)(x+2)/4(x-2)(x+2)-4(x+1)(x-2)/4(x-2)(x+2)=[4x²+8x+x+2-4(x²-2x+x-2)]/4(x+2)(x-2)=(4x²+9x+2-4x²+4x+8)/4(x+2)(x-2)=(13x+10)/4(x+2)(x-2) , dla x-2≠0 ∧ x+2≠0 czyli x≠2 ∧ x≠-2