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a_(n+1)=(2-〖5)〗^(n+2)
a_(n+1)/a_n =(〖(2-5)〗^n*〖(2-5)〗^2)/(〖(2-5)〗^n*(2-5))=-3
a zatem ciąg jest geometryczny
b)(4,x,9)
x²=4×9
x²=36
x=6 lub x=-6