Question

Rozwiaż: log_{\frac{1}{3}}\frac{x}{2-x}[/tex] \geq 0

Answer 1

 

 

 

Answer 2

log_₁/₃ [x/(2-x)] ≥ 0 

           Z: x/(2-x) > 0

               x(2-x) > 0

               x ≠ 0, x ≠2

           D = R \ {0;2}

(1/3)⁰ ≥ x/(2-x)

x/(2-x) ≤ 1   I*(2-x) > 0

x ≤ 2-x

x+x ≤ 2

2x ≤ 2  /:2

x ≤ 1

x ∈ (0;1>

------------