Rozwiąż układ równań.
i
y= x²+x-2
y= -x+1
-x+1= x²+x-2
-x²-2x+3=0
Δ= 4-4*(-1)*3
Δ=16
√Δ= 4
x1= (2-4)/(-2)
x1= 1
x2= (2+4)/(-2)
x2= -3
y1= -1+1= 0
y2= 3+1=4
xy= 240
xy-x+20y-20=240
xy=240
240-x+20y-20=240
-x+20y-20=0
y= 240/x
-x+20*(240/x)-20=0//*x
y=240/x
-x²+4800-20x=0
Δ=400-4*(-1)*4800
Δ=19600
√Δ= 140
x1= (20-140)/(-2)
x1= 60
x2= (20+140)/(-2)
x2= -80
y1= 240/60
y1=4
y2= 240/(-80)
y2= -3
Liczę na naj :)
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y= x²+x-2
y= -x+1
-x+1= x²+x-2
y= -x+1
-x²-2x+3=0
y= -x+1
Δ= 4-4*(-1)*3
Δ=16
√Δ= 4
x1= (2-4)/(-2)
x1= 1
x2= (2+4)/(-2)
x2= -3
y1= -1+1= 0
y2= 3+1=4
xy= 240
xy-x+20y-20=240
xy=240
240-x+20y-20=240
xy=240
-x+20y-20=0
y= 240/x
-x+20*(240/x)-20=0//*x
y=240/x
-x²+4800-20x=0
Δ=400-4*(-1)*4800
Δ=19600
√Δ= 140
x1= (20-140)/(-2)
x1= 60
x2= (20+140)/(-2)
x2= -80
y1= 240/60
y1=4
y2= 240/(-80)
y2= -3
Liczę na naj :)