Punkt A=(3,2) i B=(6,-5) sa koncami srednicy kola.Oblicz pole tego kola.
AB=√[(6-3)²+(-5-2)²]=√[9+49]=√58= srednica
r=√58/2
pole koła=πr²=π×(√58/2)²=π×58/4=14,5π j.²
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AB=√[(6-3)²+(-5-2)²]=√[9+49]=√58= srednica
r=√58/2
pole koła=πr²=π×(√58/2)²=π×58/4=14,5π j.²