pilne !!!
log4 (3x-2+ -2
logx 16 = 4
oblicz
log3 5 + log 3 6 - log3 10 =
log x [ 16 ] = 4 <=> x^4 = 16 = 2^4 <=> x = 2
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log 3 [ 5] + log 3 [ 6] - log 3 [10] = log 3 [ 5*6] - log 3 [10] =
= log 3 [30] - log 3 [ 10] = log 3 [ 30/10] = log 3 [ 3 ] = 1
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W I nie wiadomo co jest ?
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log x [ 16 ] = 4 <=> x^4 = 16 = 2^4 <=> x = 2
--------------------------------------------------
log 3 [ 5] + log 3 [ 6] - log 3 [10] = log 3 [ 5*6] - log 3 [10] =
= log 3 [30] - log 3 [ 10] = log 3 [ 30/10] = log 3 [ 3 ] = 1
------------------------------------------------------
W I nie wiadomo co jest ?