Question

Oblicz pole kwadartu wpisanego w okrąg

Answer 1

x^2 + 20 x + y^2 - 14 y - 6 = 0

( x + 10)^2 - 100 + ( y - 7)^2 - 49 - 6 = 0

( x + 10)^2 + ( y - 7)^2 = 155

zatem

r^2 = 155

d = 2 r

więć pole kwadratu

P = (1/2) d^2 = ( 1/2) *( 2 r)^2 = (1/2) * 4 r^2 = 2 r^2  = 2 * 155 = 310

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