Zad.1
Oblicz pole trapezu równoramiennego o podstawach 18cm i 24cm i kącie ostrym 60 stopni
a= 24cm
b= 18cm
x= 60⁰
s= (24-18)/2
s= 3cm
tg 60⁰= √3
tg 60⁰= h/s
h/s=√3
h=3√3cm
P= ½(a+b)*h
P= ½(24+18)*3√3
P= 21*3√3
P= 63√3cm²
Odp. Pole tego trapezu wynosi 63√3cm²
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a= 24cm
b= 18cm
x= 60⁰
s= (24-18)/2
s= 3cm
tg 60⁰= √3
tg 60⁰= h/s
h/s=√3
h=3√3cm
P= ½(a+b)*h
P= ½(24+18)*3√3
P= 21*3√3
P= 63√3cm²
Odp. Pole tego trapezu wynosi 63√3cm²