wyznacz dziedzinę i mijesca zerowe funcji :
a) f(x) = x²+2x/x²-4
b) f(x) = x²-1/x²-2x+1
c) f(x) = 3x²-12/x²+1
prosłbym z wyliczeniami na delte tzn wszystkie dokładnie wyliczenia jakie powinny być, dziękuję bardzo :)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
a)
b)
c)