Wyznacz wiedząc, że = a
a = log(12) 27 = log(12) 3^3 = 3 log(12) 3
1/3 a = log(12) 3
log(12) 16 = log(12) 4^2 = 2log(12) 4 = 2 ( log(12) (12/3)) =
2 ( log(12) 12 - log(12) 3 ) = 2 ( 1 - 1/3a) = 2 - 2/3a
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a = log(12) 27 = log(12) 3^3 = 3 log(12) 3
1/3 a = log(12) 3
log(12) 16 = log(12) 4^2 = 2log(12) 4 = 2 ( log(12) (12/3)) =
2 ( log(12) 12 - log(12) 3 ) = 2 ( 1 - 1/3a) = 2 - 2/3a