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a1=x
wyrazy:
x;xq; xq²
x+xq+xq²=42
x*xq*xq²=1728
x(1+q+q²)=42
x³q³=1728 /∛
x(1+q+q²)=42
xq=12→x=12/q
12/q(1+q+q²)=42 /*g/6
2+2q+2q²=7q
2q²-5q+2=0
Δ=25-16=9
√Δ=3
q=1/2→x=24
q=2→x=6
Są to liczby:
24;12 i 6
lub
6;12 i 14
czyli 6;12 i 14