Wierzchołek paraboli y = x ^2 - 4 x leży na prostej o równaniu
A y-x
B. y=x
C. y= - 2 x
D. y=4x
y = x ^2 - 4 x
p = 4/2 = 2
Δ = 16 - 4 * 1 * 0 = 16
q = -Δ/4a = -16/4 = -4
W = (p, q) = (2, -4)
odp. C
bo x = 2, y = -4
y = -2x
-4 = -2 * 2
-4 = -4
L = P
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y = x ^2 - 4 x
p = 4/2 = 2
Δ = 16 - 4 * 1 * 0 = 16
q = -Δ/4a = -16/4 = -4
W = (p, q) = (2, -4)
odp. C
bo x = 2, y = -4
y = -2x
-4 = -2 * 2
-4 = -4
L = P