oblicz wartosc parametru a dla której liczba - 2 jest miejsce zerowym wielomianu
w(x) = (4 a +2) x ^3 - 6x+3 - 2a
w(-2) = 0
w(-2) = (4 a +2) * (-2) ^3 - 6 *(-2) +3 - 2a
= (4a + 2) * (-8) + 12 + 3 - 2a
= -32a - 16 + 12 + 3 - 2a
= -34a - 1
-34a - 1 = 0
-34a = 1
a = -1/34 --------- odpowiedź
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
w(-2) = 0
w(-2) = (4 a +2) * (-2) ^3 - 6 *(-2) +3 - 2a
= (4a + 2) * (-8) + 12 + 3 - 2a
= -32a - 16 + 12 + 3 - 2a
= -34a - 1
-34a - 1 = 0
-34a = 1
a = -1/34 --------- odpowiedź