oblicz sume współczynników wielomianu
w(x) = (3-2x) ^3
w(x) = (5-3x)^3
ze wzoru (a-b)³=a³-3a²b+3ab²-b³
W(x)= 3³ - 3·3²·2x+3·3·(2x)²-(2x)³ = 27-54x+36x² -8x³
27-54+36-8=63-62=1
w(x) = (5-3x)³=5³- 3·5²·3x+3·5·(3x)²-(3x)³ = 125-225x+135x² -27x³
125-225+135-27=260-252=8
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
ze wzoru (a-b)³=a³-3a²b+3ab²-b³
W(x)= 3³ - 3·3²·2x+3·3·(2x)²-(2x)³ = 27-54x+36x² -8x³
27-54+36-8=63-62=1
w(x) = (5-3x)³=5³- 3·5²·3x+3·5·(3x)²-(3x)³ = 125-225x+135x² -27x³
125-225+135-27=260-252=8
w(x)=27-54x+36x^2-8x^3
Suma wspolczynnikow, czyli x=1
w(1)=27-54*1+36*1^2-8*1^3=27-54+36-8=1
w(x)=(5-3x)^3
w(x)=125-225x+135x^2-27x^3
w(1)=125-225*1+135*1^2-27*1^3=125-225+135-27=8