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L=(tgα-1)(ctgα+1)=tgαctgα+tgα-ctgα-1=1+tgα-ctgα-1=tgα-ctgα
L=P
tgαctgα=1
dowód
tgα=sinα/cosα
ctgα=cosα/sinα
(sinα/cosα)*(cosα/sinα)=1
(tgα-1)[(1+tgα)/tgα]=[(tgα-1)(1+tgα)]/tgα=[(tgα-1)(tgα+1)]/tgα=
=(tg²α-1)/tgα=tgα-1/tgα=tgα-ctgα+P