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xy= -8
y=-2x
x*(-2x)=-8
y=-2x
-2x²=-8/:(-2)
y=-2x
x²=4
y=-2x
x!=2 lub x2=-2 ( mamy dwa pierwiastki , stad)
y1=-2*2 y2=-2*(-2)
y1=-4 y2=4
x1=2 x2=-2
y1=-4 y2=4
Rozwiazaniem ukladu sa dwie pary liczb (x;y), sa to: (2 ; -4) oraz (-2;4)