Rozwiąż układ równań:
{2x - 2 = 2y - 3
{2x - 1 = -2(2y-3)
Rozwiąż równanie (w załączniku)
2x-2=2y-3 (I)
2y-1=2(2y-3) (II)
(I) 2x-2=2y-3 |+2
2x=2y-3+2
(II) 2x=-2(2y-3)+1
(I)=(II)
2y-1=-2(2y-3)+1
2y-1=-4y+6+1
2y-1=-4y+7 |+4y+1
6y=8
y=(8/6)=(4/3)
2x=2-(4/3)-1
2x=(8/3)-1
2x=(5/3) |:2
x=(5/6)
y=(4/3)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2x-2=2y-3 (I)
2y-1=2(2y-3) (II)
(I) 2x-2=2y-3 |+2
2x=2y-3+2
2x=2y-3+2
(II) 2x=-2(2y-3)+1
(I)=(II)
2y-1=-2(2y-3)+1
2y-1=-4y+6+1
2y-1=-4y+7 |+4y+1
6y=8
y=(8/6)=(4/3)
2x=2-(4/3)-1
2x=(8/3)-1
2x=(5/3) |:2
x=(5/6)
x=(5/6)
y=(4/3)