rozwiąż nierówność: x² - 3x +2 < 0.
x2-3x+2<0
Δ =(-3)²-4*1*2 =9-8 =1
√Δ=1
x=(3-1)/2 i x=(3+1)/2
x=1 i x=2
x∈(1;2)
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x2-3x+2<0
Δ =(-3)²-4*1*2 =9-8 =1
√Δ=1
x=(3-1)/2 i x=(3+1)/2
x=1 i x=2
x∈(1;2)