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h=2√3:⅔
h=3√3
a√3;2=3√3/:√3
a:2=3
a=6
pole trójkącika=6²√3:4=9√3j.²
duży Δ:2√3=⅓h
h=2√3;⅓=6√3
a√3:2=6√3
a=12
pole trójkata=12²√3:4=36√3j.²
zacieniowane pole=36√3-9√3=27√3j.²