w załączniku
e = 6 cm
f = 8 cm
H = 10 cm
V, Pc = ?
V = Pp × H
Pp = e×f/2 = 6cm×8cm/2 = 24 cm²
V = 24cm²×10cm
V = 240 cm³
==========
Pc = 2Pp + 4aH
Z tw. Pitagorasa liczymy a:
a² = (e/2)² + (f/2)²
a² = (6/2 cm)² + (8/2 cm)² = (9+16)cm² = 25 cm²
a = 5 cm
Pc = 2×24cm² + 4×5cm×10cm = 48cm²+200cm²
Pc = 248 cm²
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w załączniku
e = 6 cm
f = 8 cm
H = 10 cm
V, Pc = ?
V = Pp × H
Pp = e×f/2 = 6cm×8cm/2 = 24 cm²
V = 24cm²×10cm
V = 240 cm³
==========
Pc = 2Pp + 4aH
Z tw. Pitagorasa liczymy a:
a² = (e/2)² + (f/2)²
a² = (6/2 cm)² + (8/2 cm)² = (9+16)cm² = 25 cm²
a = 5 cm
Pc = 2×24cm² + 4×5cm×10cm = 48cm²+200cm²
Pc = 248 cm²
==========