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sin135°
tg150°
cos210°
ctg300°
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sin135⁰= sin(90⁰+45⁰)= cos45⁰= √2/2
tg150⁰= tg(90⁰+60⁰)= -ctg60⁰= -√3/3
cos210⁰= cos(180⁰+30⁰) = -cos30⁰= -√3/2
ctg300⁰= ctg(270⁰+30⁰)= -tg30⁰= -√3/3
A obliczyłem ! :)