Oblicz, ile waży mieszanina złożona z 4 moli CO_{2} i 120,4x10^23 cząsteczek
CO. (CO-12, O-16)
mCO=28u
1mol CO ----- 28g
4mole CO ----- xg
x = 112g
28g CO ------ 6,02*10^23 cząst.
xg CO ------- 120,4*10^23 cząst.
x = 560g CO
112g CO + 560g CO = 672g CO
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
mCO=28u
1mol CO ----- 28g
4mole CO ----- xg
x = 112g
28g CO ------ 6,02*10^23 cząst.
xg CO ------- 120,4*10^23 cząst.
x = 560g CO
112g CO + 560g CO = 672g CO