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z kata 30⁰ wynika że:
w podstawie
a=x
c=2x
b=2x√3:2=x√3
3√3=Pp×12
P p=3√3:12
Pp=¼√3
½×x√3×x=¼√3
½x²=¼
x²=½
x=¼
boki podstawy:¼;¼√3;½
obwód=¼+¼√3+½=¾+¼√3=¼(3+√3)cm