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q=-Δ/4a tzn Δ=0
tzn 1 pierwiastek
stąd
f(x)=a(x-p)²
f(2)=5
f(4)=5
5=a(2-p)²
5=a(4-p)²
(2-p)²=(4-p)²
4-4p+p²=16-8p+p²
4p=12
p=3
5=a
f(x)=5(x-3)²