v=10dm3d=1,07g/dm3m=v*dm=10*1,07m = 10,7g C2H2mC2H2=26umO2=32umC=12u2C2H2 + O2 ---> 4C + 2H2O2*26g C2H2 ------- 32g tlenu10,7g C2H2 ------- xg tlenux = 6,58g tlenu2*26g C2H2 ----- 4*12g węgla10,7g C2H2 ------ xg węglax = 9,87g węgla
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v=10dm3
d=1,07g/dm3
m=v*d
m=10*1,07
m = 10,7g C2H2
mC2H2=26u
mO2=32u
mC=12u
2C2H2 + O2 ---> 4C + 2H2O
2*26g C2H2 ------- 32g tlenu
10,7g C2H2 ------- xg tlenu
x = 6,58g tlenu
2*26g C2H2 ----- 4*12g węgla
10,7g C2H2 ------ xg węgla
x = 9,87g węgla