Uzasadnij tożsamość:
a) 2/cos²α-(tgα+ctgα)²=tg²α-ctg²α
b) 1-2sin²α*cos²α=sin⁴α+cos⁴α
2/cos ²α-[tgα+ctgα]²=tg²α-ctg²α
2/cos²α-tg²α-2tgαctgα-ctg²α-tg²α+ctg²α=0
2/cos ²α-2tg²α=2
2/cos²α-2sin²α/cos²α=2
[21-2sin²α]/cos²α=2
2[1-sin²α]/cos²α=2
2cos ²α/cos²α=2
2=2
1-2sin²αcos²α=sin⁴α+cos⁴α
1=sin⁴α+cos⁴α+2sin²αcos²α
1=[sin²α+cos²α]²
1=1²
1=1
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2/cos ²α-[tgα+ctgα]²=tg²α-ctg²α
2/cos²α-tg²α-2tgαctgα-ctg²α-tg²α+ctg²α=0
2/cos ²α-2tg²α=2
2/cos²α-2sin²α/cos²α=2
[21-2sin²α]/cos²α=2
2[1-sin²α]/cos²α=2
2cos ²α/cos²α=2
2=2
1-2sin²αcos²α=sin⁴α+cos⁴α
1=sin⁴α+cos⁴α+2sin²αcos²α
1=[sin²α+cos²α]²
1=1²
1=1