Kąt alfa jest ostry i sin alfa =5/6 oblicz tg alfa
Kąt alfa jest ostry i cos alfa =4/7 oblicz ctg alfa
sinα= 5/6
tgα= sinα/cosα= ?
cosα= √(1-sin²α)= √(1- 25/36)= 3/6= 1/3
tgα= (5/6)/ (1/3)= (5/6)*3= 15/6= 5/3
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cosα= 4/7
ctgα= cosα/sinα= ?
sinα= (1-cos²α)= √(1- 16/49)= √33/7
ctgα= (4/7)/(√33/7)= 4/√33= 4√33/33
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sinα= 5/6
tgα= sinα/cosα= ?
cosα= √(1-sin²α)= √(1- 25/36)= 3/6= 1/3
tgα= (5/6)/ (1/3)= (5/6)*3= 15/6= 5/3
-------------------------------------------------------
cosα= 4/7
ctgα= cosα/sinα= ?
sinα= (1-cos²α)= √(1- 16/49)= √33/7
ctgα= (4/7)/(√33/7)= 4/√33= 4√33/33