[√3y+(√7 + √3y)] x (√7+√3x) = ?
[√3y+(√7 + √3y)] x (√7+√3x) =
=[√3y+√7+√3y]*(√7+√3x)=
=(2√3y+√7)((√7+√3x)=
=2√21y+6xy+7+√21x=
=2√21y+√21x+6xy+7
II wersja ze zmienionym znakiem
[√3y+(√7 - √3y)] x (√7+√3x)=
=[√3y+√7-√3y]*(√7+√3x)=
=√7(√7+√3x)=
=7+√21x
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
[√3y+(√7 + √3y)] x (√7+√3x) =
=[√3y+√7+√3y]*(√7+√3x)=
=(2√3y+√7)((√7+√3x)=
=2√21y+6xy+7+√21x=
=2√21y+√21x+6xy+7
II wersja ze zmienionym znakiem
[√3y+(√7 - √3y)] x (√7+√3x)=
=[√3y+√7-√3y]*(√7+√3x)=
=√7(√7+√3x)=
=7+√21x