Prosze o pomoc bo nie jestem pewna czy dobrze zrobiłam.. a) (1/2+1/5) :1/2= b) (11 i 1/2-10 i 1/2) :.... Question from @Paulinka558

October 2018 1 37 Report

Prosze o pomoc bo nie jestem pewna czy dobrze zrobiłam.. a) (1/2+1/5) :1/2= b) (11 i 1/2-10 i 1/2) :2 i 5/6= c) (7 i 1/2-2 i 1/3) :4i 1/2= d) (7/2+2/7) :2/7= e) (3/8+1/3) : (3/4+0,5)= f) (1 i 1/2) do -1 *( 1 i 1/2) do -3= g) (1 i 2/3) do -9 :(1 i 2/3) do -7= h) ( 4/5)do -7 * (5 do -5 :4 do -5)= i) 3 do -11 [ (1/3) do15 :3 do -24]= j) 2 i 1/3 * 4 i 1/3=

madzioch

a) $(\frac{1}{2}+\frac{1}{5}) :\frac{1}{2}=(\frac{5}{10}+\frac{2}{10}) :\frac{1}{2} =\frac{7}{10} :\frac{1}{2} = \frac{7}{10} * \frac{2}{1} = \frac{7}{5} =1 \frac{2}{5}$

$(11 \frac{1}{2} -10\frac{1}{2} ) :2 \frac{5}{6} = 1: \frac{17}{6} = 1*\frac{6}{17} =\frac{6}{17}$

$(7 \frac{1}{2} -2\frac{1}{3}) :4\frac{1}{2} = (7 \frac{3}{6} -2\frac{2}{6}) :\frac{9}{2}= 5\frac{1}{6} :\frac{9}{2} = \frac{31}{6} * \frac{2}{9} = \frac{31}{27}$

$(\frac{7}{2} + \frac{2}{7} ) :\frac{2}{7} = (\frac{49}{14} + \frac{4}{14} ) *\frac{7}{2}= \frac{53}{14} *\frac{7}{2}= \frac{53}{4} = 13\frac{1}{4}$

$(\frac{3}{8}+\frac{1}{3}) : (\frac{3}{4}+0,5)= (\frac{9}{24}+\frac{8}{24}) : (\frac{3}{4}+\frac{1}{2}) = \frac{17}{24} : (\frac{3}{4}+\frac{2}{4}) = \frac{17}{24} :\frac{5}{4} =\\ \frac{17}{24} *\frac{4}{5} = \frac{17}{30}$

$(1 \frac{1}{2} ) ^{-1} *( 1 \frac{1}{2} ) ^{ -3}= (\frac{3}{2} )^{-1} *( \frac{3}{2} )^{-3} = (\frac{2}{3} )^1 * ( \frac{2}{3} )^{3} = ( \frac{2}{3} )^{1+3} =( \frac{2}{3} )^{4} =\\ \frac{16}{81}$

$(1 \frac{2}{3}) ^{ -9} :(1 \frac{2}{3} )^ {-7}= (\frac{5}{3})^{-9} : (\frac{5}{3})^{-7}= (\frac{3}{5})^{9} : (\frac{3}{5})^{7} =(\frac{3}{5})^{9-7}= (\frac{3}{5})^{2} =\\ \frac{9}{25}$

$(\frac{4}{5})^{-7} * (5 ^ {-5} :4^ {-5})= (\frac{5}{4}) ^7 * (4:5)^ {-5} = (\frac{5}{4}) ^7 * (\frac{4}{5})^ {-5} = \\ (\frac{5}{4}) ^7 * (\frac{5}{4})^ {5} = (\frac{5}{4})^ {7+5} =(\frac{5}{4})^ {12}$

$3^{ -11} [ (\frac{1}{3}) ^{15} :3^ {-24}] = 3^{-11} * [ (\frac{1}{3}) ^{15} : (\frac{1}{3})^ {24}] = 3^{-11} * [ (\frac{1}{3}) ^{15-24}] =\\ 3^{-11} * (\frac{1}{3}) ^{-9} = 3^{-11 - (-9)} = 3^{-11+9} = 3^{-2} = \frac{1}{3}^ {2} =\frac{1}{9}$