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√x² = 9 | ²
x² = 81 | √
x = √81
zatem x = -9 ∨ x = 9
Ad.2
√(2x²) = √8 | ²
2x² = 8 | ÷ 2
x² = 4 | √
x = √4
zatem x = -2 ∨ x = 2
Ad.3
√(9x² + 6x + 1) = 4 | ²
9x² + 6x + 1 = 16 | -16
9x² + 6x - 15 = 0 | /9
x² + ²/₃x - ⁵/₃ = 0
x² + ⁵/₃x - 1x - ⁵/₃ = 0
(x-1)*(x+⁵/₃) = 0
zatem x = 1 ∨ x = -⁵/₃