zad.1
Tylko jeden z ciągów: an=1+2^n, bn=3^n/4, cn=2^n-3^n jest geometryczny. wskaż ten ciąg, znajdź jego pierwszy wyraz i iloraz. oblicz sumę 23 początkowych wyrazów tego ciągu.
zad.2
oblicz x, jezeli
a) log3 x=1/3
b) log x=log3+log4
c) log x=log3+log7-1
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1.


- nie jest cięgiem geometrycznym


- jest ciągiem geometrycznym




![x= \sqrt[3]{3} x= \sqrt[3]{3}](https://tex.z-dn.net/?f=x%3D+%5Csqrt%5B3%5D%7B3%7D)










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2.
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b)
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c)