an=(3n+1)/(2n+3)
a(n-1)=[3(n-1)+1]/[2(n-1)+3]=
(3n-3+1)/(2n-2+3)=
(3n-2)/(2n+1)
odp. b]
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an=(3n+1)/(2n+3)
a(n-1)=[3(n-1)+1]/[2(n-1)+3]=
(3n-3+1)/(2n-2+3)=
(3n-2)/(2n+1)
odp. b]