Question

2log3=x dan 2log 10=y. Nilai 6log 120 adalah ..

Answer 1

Nilai 6 log 120=>
^6log 120
=²log 120 / ²log 6
=(²log 2²×3×10) / (²log 2×3)
=(²log 2² + ²log 3 + ²log 10)/(²log 2 +²log 3)
=(2 ²log 2 +²log 3+²log 10)/(²log 2+²log3)
=(2 + x + y) / (1+ x)

Answer 2

²log 3 = x
²log 10 = y
²log 5 = y-1

⁶log 120 = ²log 120/²log 6
              = ²log (8.3.5)/²log (2.3)
              = (²log 8 + ²log 3 + ²log 5)/(²log 2 + ²log 3)
              = (3+x+(y-1))/(1+x)
              = (x+y+2)/(1+x)