1.usun niewymiernosc z mianownika :
a) 2 kreska ulamkowa, na dole pierwiastek z 3
b) 4 , kreska ulamkowa, na dole 3 pierwiastek z 2
c) 1, kreska ulamkowa, na dole 6+ pierwiastek z 2
d) 2 pierwiastek z 2, na dole pierwiastek z 5 + 4
e)2, kreska ulamkowa, na dole 4-3 pierwiastek z 2
f) 2pierwiastek z 3-1, na dole 2 pierwiastek z 3 +2
g) 1 , na dole pierwiastek z 3 - pierwiastek z 2
2. rozwiaz rownanie :
a) (x-5)(x+5)= x^2 - 100x
b)4(x+2)^2-(2x-1)^2=-8
3.usun nierwymiernosc z mianownika :
a) 1, a na dole pierwiastek z 2
b)1, a na dole pierwiastek z 15
c)1, a na dole 2- pierwiastek z 3
d)pierwiastek z 2 a na dole pierwiastek 3 +2
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1.
a)![\frac{2}{\sqrt{3}}* \frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3} \frac{2}{\sqrt{3}}* \frac{\sqrt{3}}{\sqrt{3}}=\frac{2\sqrt{3}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B%5Csqrt%7B3%7D%7D%2A+%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B%5Csqrt%7B3%7D%7D%3D%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B3%7D)
b)![\frac{4}{3\sqrt{2}}*\frac{3\sqrt{2}}{3\sqrt{2}}=\frac{12\sqrt{2}}{18}=\frac{2\sqrt{2}}{3} \frac{4}{3\sqrt{2}}*\frac{3\sqrt{2}}{3\sqrt{2}}=\frac{12\sqrt{2}}{18}=\frac{2\sqrt{2}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%5Csqrt%7B2%7D%7D%2A%5Cfrac%7B3%5Csqrt%7B2%7D%7D%7B3%5Csqrt%7B2%7D%7D%3D%5Cfrac%7B12%5Csqrt%7B2%7D%7D%7B18%7D%3D%5Cfrac%7B2%5Csqrt%7B2%7D%7D%7B3%7D)
c)![\frac{1}{6+\sqrt{2}}*\frac{6- \sqrt{2}}{6- \sqrt{2}}=\frac{6- \sqrt{2}}{36-2}=\frac{6- \sqrt{2}}{34}=\frac{3- \sqrt{2}}{17} \frac{1}{6+\sqrt{2}}*\frac{6- \sqrt{2}}{6- \sqrt{2}}=\frac{6- \sqrt{2}}{36-2}=\frac{6- \sqrt{2}}{34}=\frac{3- \sqrt{2}}{17}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%2B%5Csqrt%7B2%7D%7D%2A%5Cfrac%7B6-+%5Csqrt%7B2%7D%7D%7B6-+%5Csqrt%7B2%7D%7D%3D%5Cfrac%7B6-+%5Csqrt%7B2%7D%7D%7B36-2%7D%3D%5Cfrac%7B6-+%5Csqrt%7B2%7D%7D%7B34%7D%3D%5Cfrac%7B3-+%5Csqrt%7B2%7D%7D%7B17%7D)
d)![\frac{2\sqrt{2}}{\sqrt{5}+{4}}*\frac{\sqrt{5}-{4}}{\sqrt{5}-{4}}=\frac{2\sqrt{10}-8\sqrt{2}}{11} \frac{2\sqrt{2}}{\sqrt{5}+{4}}*\frac{\sqrt{5}-{4}}{\sqrt{5}-{4}}=\frac{2\sqrt{10}-8\sqrt{2}}{11}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Csqrt%7B2%7D%7D%7B%5Csqrt%7B5%7D%2B%7B4%7D%7D%2A%5Cfrac%7B%5Csqrt%7B5%7D-%7B4%7D%7D%7B%5Csqrt%7B5%7D-%7B4%7D%7D%3D%5Cfrac%7B2%5Csqrt%7B10%7D-8%5Csqrt%7B2%7D%7D%7B11%7D)
e)![\frac{2}{4-3\sqrt{2}}=\frac{4+3\sqrt{2}}{4+3\sqrt{2}}=\frac{8+6\sqrt{2}}{2}={{4+3\sqrt{2}} \frac{2}{4-3\sqrt{2}}=\frac{4+3\sqrt{2}}{4+3\sqrt{2}}=\frac{8+6\sqrt{2}}{2}={{4+3\sqrt{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B4-3%5Csqrt%7B2%7D%7D%3D%5Cfrac%7B4%2B3%5Csqrt%7B2%7D%7D%7B4%2B3%5Csqrt%7B2%7D%7D%3D%5Cfrac%7B8%2B6%5Csqrt%7B2%7D%7D%7B2%7D%3D%7B%7B4%2B3%5Csqrt%7B2%7D%7D)
f)![\frac{2\sqrt{3}-1}{2\sqrt{3}+2}*\frac{2\sqrt{3}-2}{2\sqrt{3}-2}=\frac{12-4\sqrt{3}-2\sqrt{3}-2}{12-2}=\frac{10-6\sqrt{3}}{10}=\frac{5-3\sqrt{3}}{5} \frac{2\sqrt{3}-1}{2\sqrt{3}+2}*\frac{2\sqrt{3}-2}{2\sqrt{3}-2}=\frac{12-4\sqrt{3}-2\sqrt{3}-2}{12-2}=\frac{10-6\sqrt{3}}{10}=\frac{5-3\sqrt{3}}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Csqrt%7B3%7D-1%7D%7B2%5Csqrt%7B3%7D%2B2%7D%2A%5Cfrac%7B2%5Csqrt%7B3%7D-2%7D%7B2%5Csqrt%7B3%7D-2%7D%3D%5Cfrac%7B12-4%5Csqrt%7B3%7D-2%5Csqrt%7B3%7D-2%7D%7B12-2%7D%3D%5Cfrac%7B10-6%5Csqrt%7B3%7D%7D%7B10%7D%3D%5Cfrac%7B5-3%5Csqrt%7B3%7D%7D%7B5%7D)
g)![\frac{1}{\sqrt{3}-2}*\frac{\sqrt{3}+2}{\sqrt{3}+2}=\frac{\sqrt{3}+2}{5} \frac{1}{\sqrt{3}-2}*\frac{\sqrt{3}+2}{\sqrt{3}+2}=\frac{\sqrt{3}+2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D-2%7D%2A%5Cfrac%7B%5Csqrt%7B3%7D%2B2%7D%7B%5Csqrt%7B3%7D%2B2%7D%3D%5Cfrac%7B%5Csqrt%7B3%7D%2B2%7D%7B5%7D)
2.
a)(x-5)(x+5)= x^2 - 100x
x^2-25=x^-100x
-25=-100x/(-100)
x=0,25
b)4(x+2)^2-(2x-1)^2=-8
4(x^2+4)-4x^2+1=-8 4x^2+4x^2=-8-16-1 0=25 sprzeczność brak rozwiązań 3. a)