Zreagowalo 4,7g fenolu i 120g 14% roztworu wodorotlenku potasu. Ile gram soli sie utworzylo?
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mKOH=56u
Cp=14%
mr=120g
ms=Cp*mr/100%
ms=14*120/100
ms = 16,8g KOH
C₆H₅OH + KOH --->C₆H₅OK + H₂O
94g fenolu ---- 56g kOH
4,7g fenolu ---- xg KOH
x = 2,8g KOH (KOH został użyty w nadmiarze)
94g fenolu ---- 132g soli
4,7g fenolu --- xg soli
x = 6,6g soli