Zapisz w postaci sumy algebraicznej
a 2(a+b) * c -(2ac-bc+1)
b 5(x-z) +2(z-x)
c 2x²(x-5)-3x(x²-3x+5)
d 6(a²+b + 1 )-6(a²- 1 ) -3(b + 1)
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3 2 3
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a) 2a+2b*c-2ac+bc-1=2ac+2bc-2ac+bc-1=3bc-1
b)5x-5z+2z-2x=3x-3z
c)2x^3-10x^2-3x^3+9x^2-15x=-x^3+x^3
d)6a^2+6b+6-6a^2+6-3b-3=3b+3
:)