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b=-5 pierw 3 stop z 3 - 3 pierw 3 stop z 9
c pierw. z 11+ 6 pierw 3 stop z 11
reszte sama mam zadaną
b) ∛-3+2∛9-4∛3-5∛9= -∛3-4∛3+2∛9-5∛9=-5∛3-3∛9
c)2√11-∛-11+7∛11-√11= 2√11-√11-∛11+7∛11= √11-6∛11
d) -6(√14-2)-4√14:2= -6√14+12-4√14:2= -6√14-4√14+12:2=-6√14-4√14+6= -2√14+6
e) 2(√13+3)-4(√13-3)= 2√13+6-4√13-12= 2√13-4√13+6-12= -2√13-6
f) -(∛2-2∛6)+3(5∛2-∛-6)= 1∛2-2∛6+15∛2-3∛6= ∛2+15∛2-2∛6-3∛6= 16∛2-5∛6
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