Question

Zamień ułamek na ułamki o mianownikach:

a)x² +10x +9

b) x² - 5x -6

c) x² +5x +4

d)x³+1

Answer 1

c)\ 

 

 

proszę bardzo ;)

Answer 2

a)

x²+10x+9=

x²+x+9x+9=

x(x+1)+9(x+1)=

(x+9)(x+1)

 

(x-1)/(x+1)=

(x-1)(x+9)/(x+1)(x+9)=

(x²+9x-x-9)/(x²+10x+9)=

(x²+8x-9)/(x²+10x+9)

 

b)

x²-5x-6=

x²+x-6x-6=

x(x+1)-6(x+1)=

(x-6)(x+1)=

 

(x-1)/(x+1)=

(x-1)(x-6)/(x+1)(x-6)=

(x²-6x-x+6)/(x²-5x-6)=

(x²-7x+6)/(x²-5x-6)

 

c)
x² +5x +4=

x²+x+4x+4=

x(x+1)+4(x+1)=

(x+4)(x+1)=

 

(x-1)/(x+1)= 

(x-1)(x+4)/(x+1)(x+4)=

(x²+4x-x-4)/(x²+5x+4)=

(x²+3x-4)/(x²+5x+4)

 

d)

x³+1=

(x+1)(x²-x+1)

 

(x-1)/(x+1)= 

(x-1)(x²-x+1)/(x+1)(x²-x+1)=

(x³-x²+x-x²+x-1)/(x³+1)=

(x³-2x²+2x-1)/(x³+1)