Zadania z trygonometrii w załączniku. Błagam..
1 a)
b)sin -
cos +
tg-
ctg-
sin=-0,4
1-sin^2x=cos^2x<=>cos=
tg=\
ctg=1/tg
d) |ctg|=<=>ctg= v vtg=-
ctgx =<=>x=<=>x= i x=
ctgx=-<=>x=-<=>x= i x=
2cos(2x+pi/2)=
cos(2x+pi/2)=<=>2x+pi\2=<=>
2x+pi/2=pi/6+2kpi v 2x+pi/2=-pi/6+2kpi
x=-2pi/6+kpi v x=-4pi/6 +kpi odp. x=2/3pi i 1/3pi i10/6pi i 8/6pi
5.po przeliczeniu cos600=-cos60=-1/2
sin 405=sin45
sin540=cos90=0
cos480=-sin30=-1/2
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1 a)
b)sin -
cos +
tg-
ctg-
sin=-0,4
1-sin^2x=cos^2x<=>cos=
tg=\
ctg=1/tg
d) |ctg|=<=>ctg= v vtg=-
ctgx =<=>x=<=>x= i x=
ctgx=-<=>x=-<=>x= i x=
2cos(2x+pi/2)=
cos(2x+pi/2)=<=>2x+pi\2=<=>
2x+pi/2=pi/6+2kpi v 2x+pi/2=-pi/6+2kpi
x=-2pi/6+kpi v x=-4pi/6 +kpi odp. x=2/3pi i 1/3pi i10/6pi i 8/6pi
5.po przeliczeniu cos600=-cos60=-1/2
sin 405=sin45
sin540=cos90=0
cos480=-sin30=-1/2