zad1
a) 13x-8(3x-2) = -7x - 5(12-3x)
b) 7(2x-1)-6(11-x) = 3(x+4)
c) (x+5)(x+2)-3(4x-3)= (x-5)^2
d) 12-2(x-1)^2 = 4(x-2)-(x-3)(2x-5)
e) (x-3)(x+3)-(2x-1)^2 = x(6-3x)-9
f) 3(x+2)^2 + (2x-1)^2 -7(x+3)(x-3)=28
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a) 13x-8(3x-2) = -7x - 5(12-3x)
13x - 24x +16 +7x+60-15x=0
-19x=-76
x=4
b) 7(2x-1)-6(11-x) = 3(x+4)
14x-7-66+6x-3x-12=0
17x=88
x=5
c) (x+5)(x+2)-3(4x-3)= (x-5)^2
x^2+7x+10-12x+9-x^2+10x-25=0
5x=6
x=6/5
d) 12-2(x-1)^2 = 4(x-2)-(x-3)(2x-5)
12-2x^2 +4x -2 -4x+8+2x^2-11x+15=0
-11x=-33
x=3
e) (x-3)(x+3)-(2x-1)^2 = x(6-3x)-9
x^2-9-4x^2+4x-1-6x+3x^2+9=0
-2x=1
x=-(1/2)
f) 3(x+2)^2 + (2x-1)^2 -7(x+3)(x-3)=28
3x^2+12x+12+4x^2-4x-1-7x^2+63-28=0
8x=-48
x= -(5 i 3/4)
moje rozwiazanie jest w załaczniku. ; )))