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Zad. 1. bok kwadratu = 4√2
d (przekątna) = a√2
d = 4√2 razy √2 = 4 razy 2 = 8
h trójkata rownobocznego = a√3/2
8 = a√3 przez 2 / razy 2
a√3 = 16 /: √3
a = 16 / √3 = 16 razy √3 / √3 razy √3
a = 16 razy √3 / 3
a = 5⅓ √3