zad 1 Rozwiąż równania:
a)
b)
c)
d)
a) (2x-5)(x+2)=(x-1)(2x+3)
-2x-5x-10=+3x-2x-3
-8x=7 /:(-8)
x=
b) 5(2x+2)=x(-x)
10x+10=-
+10x-10=0
delta=
delta=-4*1*10
delta=100-40
delta=60
=
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a) (2x-5)(x+2)=(x-1)(2x+3)
-8x=7 /:(-8)
x=![-\frac{7}{8} -\frac{7}{8}](https://tex.z-dn.net/?f=-%5Cfrac%7B7%7D%7B8%7D)
b) 5(2x+2)=x(-x)
10x+10=-![x^2 x^2](https://tex.z-dn.net/?f=x%5E2+)
delta=![b^2-4ac b^2-4ac](https://tex.z-dn.net/?f=b%5E2-4ac)
delta=
-4*1*10
delta=100-40
delta=60