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mC₂H₅Cl=64,5u
mC₂H₅OH=46u
C₂H₅Cl + KOH --H₂O--> C₂H₅OH + KCl
64,5g chlorku ----- 46g etanolu
258g chlorku ----- xg etanolu
x = 184g etanolu
184g etanolu ---- 100%
170g etanolu ----- x%
x = 92,4%