x:(y+2)=4
x:(y-2)=5
pilnie proszę o rozwiązanie tego układu równań
x:(y+2)=4/*-1 -x:(y+2)=-4 | 2y=1/:2 y=0,5
x:(y-2)=5 x:(y-2)=5 |+ x:(y-2)=5 x:(0,5-2)=5/*x
y=0,5 y=0,5
1,5=5*x/:5 1,5/5=x
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x:(y+2)=4/*-1 -x:(y+2)=-4 | 2y=1/:2 y=0,5
x:(y-2)=5 x:(y-2)=5 |+ x:(y-2)=5 x:(0,5-2)=5/*x
y=0,5 y=0,5
1,5=5*x/:5 1,5/5=x