x2+y2-12x+24y+36=0 tu chodzi oanalize rownania okregu w postaci kanonicznej
x^2 + y^2 - 12 x + 24 y + 36 = 0
(x - 6)^2 - 36 + ( y + 12)^2 - 144 + 36 = 0
( x - 6)^2 + ( y + 12)^2 = 144
(x - 6)^2 + ( y + 12)^2 = 12^2
Środkiem tego okręgu jest punkt S = ( 6; - 12) , a r = 12
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x^2 + y^2 - 12 x + 24 y + 36 = 0
(x - 6)^2 - 36 + ( y + 12)^2 - 144 + 36 = 0
( x - 6)^2 + ( y + 12)^2 = 144
(x - 6)^2 + ( y + 12)^2 = 12^2
Środkiem tego okręgu jest punkt S = ( 6; - 12) , a r = 12
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