Question

wykonaj dzialania:

bardzo prosze o szybkie rozwiąznaie:)

Answer 1

a)

2x+4

------

4-x

 

b)

2x(x-2)

---------

x+2

 

 

(to ułamki)

Answer 2

a)

x/x-4) - (x+1)/(4-x) + (2x+3)/(x-4) =x/(x-4) + (x+1)/(x-4) + (2x+3)/(x-4) =

=(x+x+1+2x+3)/(x-4) =

= (4x+4)/(x-4)

b)

(2x2 + 6x)/(x^2 + 4x + 4) : (x^2 + 6x + 9)/(x^2 - 4 =

= 2x(x+3)/(x+2)^2 : (x+3)^2/[(x+2)(x-2)] =

= 2x(x3)/(x+2)^2 * (x+2)(x-2)/(x+3)^2 =

= 2x(x-2)/[(x+2)(x+3)]