rozwiąż:
bardzo prosze o szybkie rozwiąznaie:))
D=R\{-1,2}
(2x-3)/(x+1) -1 = x/(x-2)
x =/= -1
x =/= 2
D = R \ {-1, 2}
(2x-3-x-1)/(x+1) = x/(x-2)
(x-4)/(x+1) = x/(x-2)
(x-4)(x-2) = x(x+1)
x^2 -2x - 4x + 8 = x^2 + x
-7x = -8 /:(-7)
x = 8/7
x = 1 1/7
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D=R\{-1,2}
(2x-3)/(x+1) -1 = x/(x-2)
x =/= -1
x =/= 2
D = R \ {-1, 2}
(2x-3)/(x+1) -1 = x/(x-2)
(2x-3-x-1)/(x+1) = x/(x-2)
(x-4)/(x+1) = x/(x-2)
(x-4)(x-2) = x(x+1)
x^2 -2x - 4x + 8 = x^2 + x
-7x = -8 /:(-7)
x = 8/7
x = 1 1/7
=========