Question

Rozwiąż układy metoda podstawienia
c)2x+3y=14 e)1/2x-3/4y=0
3x-2y=8 2/3x+ 1 1/4y=9
a)2x-2y=7 f)3x+4y=1 2/3
4x+3y=21 6x+3y=1 1/4

/- ułamek
prosze o pomoc;p

Answer 1

2x+3y=14:2
3x-2y=8

x+2/3y=7
3x-2y=8

x=7-2/3y
3(7-2/3y)-2y=8

x=7-2/3y
21-2y-2y=8

-4y=8-21
-4y=13/4=3 1/4
x=7-2/3(13/4)=29/6



2x-2y=7/2
4x+3y=21

x=7/2-y
4(7/2-y)+3y=21

x=7/2-y
14-y=21
y=-7

x=7/2+7=10 1/2

1/2x-3/4y=0/4
2/3x+1 1/4y=9

2x-3y=0/2
2/3x+5/4y=9

x=3/2y
2/3*3/2y+5/4y=9

x=3/2y
9/4y=9/9/4
y=4
x=3/2*4=6


3x+4y=1 2/3
6x+3y=1 1/4 /3

3x+4y=5/3
2x+y=5/12

3x+4y=5/3
y=5/12-2x

3x+4(5/12-2x)=5/3
3x+5/3-8x=5/3
-5x=0
x=0
co do tego ostatniego niejestem pewna