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A = (x,0), a B = (0,y)
S = (-3,5)
xs = (xA+xB)/2
(-3) = (xa+0)/2
A = (-6,0)
ys = (yA+yB)/2
5 = (0+yB)/2
10 = yB
B = (0,10)
6.
6+3+x = x+9
Ilość białych kul = 6
Prawdopodobieństwo wylosowania białej kuli = 1/3
6/(x+9)=1/3
x + 9 = 18
x = 9
7.
a). N = 5*4*3 = 60
b). N = 4*4*4=64
c). N = 7*8*4=224